3(2logy) – 2logy2 + 2log1/y=...
Matematika
Sashafzhr07
Pertanyaan
3(2logy) – 2logy2 + 2log1/y=...
1 Jawaban
-
1. Jawaban nabilap0
SIfat Logaritma:
ᵃlog a = 1
ᵃlog b + ᵃlog c = ᵃlog(b.c)
ᵃlog b - ᵃlog c = ᵃlog(b/c)
ᵃlog 1 = 0
=Jawaban==
3(²logy) – ²logy² + ²log1/y
= ²logy³ - ²logy² + ²log1/y
= ²log(y³/y²) + ²log1/y
= ²logy + ²log1/y
= ²log(y.1/y)
= ²log1
= 0