nilai 3 log 300 - 3 log 50 - 3 log 2 + 3 log 3

3 log ( 300 : 50 ) - 3 log 2 + 3 log 3
3 log ( 6 : 2 ) + 1
3 log 3 + 1
1 + 1 = 2

SIfat Logaritma:
ᵃlog a = 1
ᵃlog b + ᵃlog c = ᵃlog(b.c)
ᵃlog b - ᵃlog c = ᵃlog(b/c)
ᵃlog 1 = 0

=Jawaban==
³log300 - ³log50 - ³log2 + ³log3
= ³log(300/50) - ³log2 + 1
= ³log6 - ³log2 + 1
= ³log(6/2) + 1
= ³log3 + 1
= 1 + 1
= 2