tentukan persamaan garis yg melalui titik(-3,5)dan (0,-3)

[tex] y_{2} [/tex]-[tex] y_{1} [/tex]
--------------
[tex] x_{2} [/tex]-[tex] y_{1} [/tex]

[tex] \frac{-3-(5)}{0-(-3)} [/tex]


-[tex] \frac{-8}{3} [/tex]

y - y1. x - x1
-------- = ----------
y2 - y1. x2 - x1

y - 5. x -(-3)
-------- = ---------
3 - 5. 0 - (-3)

y-5. x + 3
------- = ---------
-2. 3

3(y-5). = -2(x+3)
3y-15. = -2x -6
3y+2x-15+6=0
3y+2x-9=0