salah 1 faktor x²-7x-12

[tex]x^2-7x-12=0 \\ \\ x^2-7x+( \frac{7}{2})^2-12+=( \frac{7}{2})^2 \\ \\ x^2-7x+(\frac{7}{2})^2=12+\frac{49}{4} \\ \\ (x- \frac{7}{2})^2= \frac{73}{2} \\ \\ x- \frac{7}{2}=\pm \sqrt{\frac{73}{2} } \\ \\ x= \frac{7}{2} \pm\sqrt{\frac{73}{2} }[/tex]

Jadi akar-akarnya adalah:

[tex]x_1= \frac{7}{2} +\sqrt{\frac{73}{2} } \\ \\ x_2= \frac{7}{2} -\sqrt{\frac{73}{2} } [/tex]