1. Diketahui rumus fungsi f(x) = ax + 2, jika f(2) = 6, maka nilai a adalah.... 2. Diketahui rumus fungsi f(x) = ax + b, jika f(-1) = 5 dan f(2) = -1, maka nila

1) f(x) = ax + 2
f(2) = 2a + 2 = 6
2a = 6 - 2
2a = 4
a = 2

2) f(x) = ax + b
f(-1) = - a + b = 5
f(2) = 2a + b = - 1
-------------------------(-)
- 3a = 6
a = - 2
-a + b = 5
- (-2) + b = 5
2 + b = 5
b = 5 - 2
b = 3
nilai a + b
= - 2 + 3
= 1

1.f(x)=ax+2
  -f(2)=a(2)+2=6
          2a+2=6
          2a=6-2
          2a=4  
          a=4/2
          a=2
Maaf saya hanya bisa menjawab nomor 1