dijawab ya pleaseeeeeeeeeeee

9.
[tex] \frac{1}{b} - \frac{3}{ab} [/tex]
[tex] \frac{a}{ab} + \frac{3}{ab} [/tex]
[tex] \frac{a + 3}{ab} [/tex]
10.
[tex](x - \frac{1}{x} ) {}^{2} [/tex]
[tex](x - \frac{1}{x} )(x - \frac{1}{x} )[/tex]
[tex]x^{2} - \frac{2}{x} + \frac{1}{ {x}^{2} } [/tex]

Soal No. 8
[tex]= \frac{3}{a - b} - \frac{2}{a + b} \\ \\ = \frac{3(a+b) - 2(a-b)}{(a-b)(a+b)} \\ \\ = \frac{3a + 3b -2a + 2b}{(a-b)(a+b)} \\ \\ = \frac{a+5b}{(a-b)(a+b)} [/tex]

Soal No. 9
[tex]= \frac{1}{b} + \frac{3}{ab} \\ \\ = \frac{1(ab) + 3(b)}{(b)(ab)} \\ \\ = \frac{ab + 3b}{(b)(ab)} \\ \\ = \frac{b(a+3)}{b(ab)} \\ \\ = \frac{a+3}{ab} [/tex]

Soal No. 10
[tex]= (x- \frac{1}{x} )^{2} \\ \\ = x^{2} - 2.x. \frac{1}{x} + ( \frac{1}{x} )^2 \\ \\ = x^{2} -2+ \frac{1}{x^{2}} [/tex]
Dikalikan dengan x², maka hasilnya adalah
[tex]= x^{4} - 2 x^{2} + 1 [/tex]