Selesaian sistem persamaan 2x + 3y = 12 dan 3x + 2y = 8 adalah x = a dan y = b Nilai a+b adalah…

2x + 3y = 12. 3
3x + 2y = 8 (dikali) 2
6x + 9y = 36
6x + 4y = 16. (dikurangi)
5y = 20
y = 20/5 = 4
substitusikan
2x + 3(4) = 12
2x + 12 = 12
2x = 12 -12
2x = 0
x = 0. buktikan. 2x + 3y = 12
2(0) + 3(4) =12
0 + 12 =12
x = a (0)
y = b (4)
a + b
0 + 4 = 4

jawabannya 4