menggunakan metode eliminasi &subtitusi(campuran) 1.2x-5y+20=0 2y-5x=24 2.3x-2y=8 4x+y=7 3.7x-2y=14 5x=8y-19 4.x+3y=5 3x+y=-1 5.x-y=0 x+y=4 tolong dijawab ya so
Matematika
sayla23
Pertanyaan
menggunakan metode eliminasi &subtitusi(campuran)
1.2x-5y+20=0
2y-5x=24
2.3x-2y=8
4x+y=7
3.7x-2y=14
5x=8y-19
4.x+3y=5
3x+y=-1
5.x-y=0
x+y=4
tolong dijawab ya
soalnya bsk dikumpul
1.2x-5y+20=0
2y-5x=24
2.3x-2y=8
4x+y=7
3.7x-2y=14
5x=8y-19
4.x+3y=5
3x+y=-1
5.x-y=0
x+y=4
tolong dijawab ya
soalnya bsk dikumpul
1 Jawaban
-
1. Jawaban Roselly11
2.) 3x-2y=8 (×1)
4x+y=7 (×2)
=> (3x-2y=8)+(8x+2y=14)
=> 11x=22
=> x=2 => 4x+y=7
=> 4(2)+y=7
=> y= -1
4.) x+3y=5(×3)
3x+y=-1(×1)
=>(3x+9y=15)-(3x+y=-1)
=>8y=16
=> y= 2
=> 3x+9y=15
=>3x+9(2)=15
=>3x+18=15
=>3x=15-18
=>3x= -3
=>x= -1
5.) (x-y=0)-(x+y=4)
=>-2y=-4
=>y=2
(x-y=0)+(x+y=4)
=>2x=4
=> x=2