Hasil pemfaktoran dari 9x2-3x-9

bukan akar bulat. misal dicari dulu akar2nya dg melengkapkan kuadrat
9x² - 3x - 9 = 0
x² - (1/3)x = 3
x² - (1/3)x + (1/6)² = 3 + (1/6)²
(x - 1/6)² = 37/36
x - 1/6 = ±√(37/36)
x = 1/6 ± (1/6)√37
faktor2nya (x - x1)(x - x2)
= (x - (1/6 + (1/6)√37)(x - (1/6 - (1/6)√37)
= (x - 1/6 - (1/6)√37)(x - 1/6 + (1/6)√37)
atau
= (1/6)(6x - 1 - √37)(1/6)(6x - 1 + √37)
= (1/36)(6x - 1 - √37)(6x - 1 + √37)