hasil dari 2 3per4 + 1 1per2 -(-2per3) tolong ya pake cara

[tex]2 \frac{3}{4} + 1\frac{1}{2} - ( - \frac{2}{3} ) \\ = \frac{11}{4} + \frac{6}{4} + \frac{2}{3} \\ = \frac{17}{4} + \frac{2}{3} \\ = \frac{51}{12} + \frac{8}{12} \\ = \frac{59}{12} \\ = 4 \frac{11}{12} [/tex]

2 [tex] \frac{3}{4} [/tex] + 1 [tex] \frac{1}{2} [/tex] - (-[tex] \frac{2}{3} [/tex])
= [tex] \frac{11}{4} [/tex] + [tex] \frac{3}{2} [/tex] + [tex] \frac{2}{3} [/tex]
= [tex] \frac{33 + 18 + 8}{12} [/tex] = [tex] \frac{59}{12} [/tex]
= 3 [tex] \frac{14}{15} [/tex]

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