Matematika

Pertanyaan

2√12-3√18 per 4√18+√32

1 Jawaban

  • MAPEL = MATEMATIKA
    KELAS = 9
    BAB = AKAR KUADRAT

    [tex] \frac{2 \sqrt{12} \: - \: 3 \sqrt{18} }{4 \sqrt{18} \: + \: \sqrt{32} } \\ = \frac{2 \sqrt{4 \times 3} - 3 \sqrt{9 \times 2} }{ 4 \sqrt{9 \times 2} - \sqrt{16 \times 2} } \\ = \frac{4 \sqrt{3} - 9 \sqrt{2} }{12 \sqrt{2} + 4 \sqrt{2} } \\ = \frac{4 \sqrt{3} - 9 \sqrt{2} }{16 \sqrt{2} } ( \times \sqrt{2} ) \\ = \frac{4 \sqrt{6} - 9 \sqrt{4} }{16 \sqrt{4} } \\ = \frac{4 \sqrt{6} - 18 }{32} \\ = \frac{ \sqrt{6} - 18 }{8} [/tex]

    semoga membantu

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