jika nilai a= -1/2, b= 1/3 maka nilai dari a 1/b adalah

[tex] = a \frac{1}{b} \\ = \frac{(axb) + 1}{b} \\ = \frac{( - \frac{ 1}{2} \times \frac{1}{3} ) + 1}{ \frac{1}{3} } \\ = \frac{ - \frac{1}{6} + 1 }{ \frac{1}{3} } \\ = \frac{ - \frac{1}{6} + \frac{6}{6} }{ \frac{1}{3} } \\ = \frac{5}{6} \div \frac{1}{3} \\ = \frac{5}{6} \times \frac{3}{1} \\ = \frac{15}{6} \\ [/tex]