penyelesaian dari sistem persamaan {x2-y2=25 dan x2+y2 = 25

[tex] {x}^{2} - {y}^{2} = 25 \\ {x}^{2} + {y}^{2} = 25 \\ dijumlah \\ 2 {x}^{2} = 50 \\ {x}^{2} = \frac{50}{2} \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5 \\ substitusi \: nilai \: x \\ {x}^{2} - {y}^{2} = 25 \\ {5}^{2} - {y}^{2} = 25 \\ {y}^{2} = 25 - 25 \\ {y}^{2} = 0 \\ y = \sqrt{0} \\ y = 0[/tex]