Bantu dong....pakai jalan ya

19.
[tex] \frac{x + 1}{4y} \div \frac{x + 4}{8y} \\ = \frac{x + 1}{4y} \times \frac{8y}{x + 4} \\ = \frac{8y(x + 1)}{4y(x + 4)} \\ = \frac{2(x + 1)}{x + 4} [/tex]