Bantu lg dong...pakai jalan...

[tex]= \frac{3}{2x}- \frac{y+1}{3xy} \\ \\ = \frac{3(3xy)-2x(y+1)}{(2x)(3xy)} \\ \\ = \frac{9xy-2xy-2x}{(2x)(3xy)} \\ \\ = \frac{7xy-2x}{(2x)(3xy)} \\ \\ = \frac{x(7y-2)}{x(6xy)} \\ \\ = \frac{7y-2}{6xy} [/tex]

Jawaban (B)