jika 2log 3=x,7log 3=y,maka 14log63=

Diket :
2log3 = x
7log3 = y
3log2 = 1/x
3log7 = 1/y

14log63 =...
= 3log14/3log63
= 3log2 + 3log7 / 3log7 + 3log9
= 3log2 + 3log7 / 3log7 + 3log3^2
= 1/x+1/y / 1/y+2
= x+y/xy / 3y/y
= x+y/x(3y)
= x+y/3xy

Maaf jika ada kesalahan :)

Diketahui: 2log3=X, 7log3=Y,
maka: 14log63=
= (2log63) / (2log14)
= (2log9×7) / (2log7×2)
= (2log9 + 2log7) / (2log7 + 2log2)
= (2 2log3 + 2log7) / (2log7 + 1)
= (2X + 2log7) / (1 + 2log7)
=.....

Akan tetapi jika Y= 3log7 maka XY= 2log7. Hasilnya = (2X +XY) / (1+XY)