tolong bantu................... pakai cara ya.....

[tex] \frac{9bc + bcx {}^{2} }{3c {}^{2}x } \\ = \frac{c \times (9b + bx {}^{2} )}{3c {}^{2} x} \\ = \frac{9b + bx {}^{2} }{3cx} [/tex]