integral 3x^2(2x+7) dx

∫ 3x² (2x + 7) dx
= ∫ 6x³ + 21x² dx
= (6/4)x⁴ + (21/3)x³ + C
= (3/2)x⁴ + 7x³ + C

= [tex] \frac{3}{2}x^4+7x^3+C [/tex]

Jawabannya:
integral 3x²(2x+7) dx
= integral 6x³+21x² dx
= (6/4)x⁴+(21/3)x³+c
= (3/2)x⁴+7x³+c
= 3/2 x⁴+7x³+c

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