f(x)=(x-8)(x^2+2x+1) tentukan nilai f'(x)
Matematika
rismadayanti02
Pertanyaan
f(x)=(x-8)(x^2+2x+1) tentukan nilai f'(x)
1 Jawaban
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1. Jawaban FieraAri
f(x) = (x - 8)(x² +2x + 1)
u = x - 8
u' = 1
v = x² + 2x + 1
v' = 2x + 2
f'(x) = u'v + uv'
f'(x) = (1)(x² + 2x + 1) + (2x+2)(x - 8)
f'(x) = x² + 2x + 1 + 2x² -14x - 16
f'(x) = 3x² - 12x - 15