Matematika

Pertanyaan

1/5 5log25 - 3/5 5log1/125+7/10 5log1/25=
1/5 5log25 - 3/5 5log1/125+7/10 5log1/25=

2 Jawaban

  • 1/5 5'log 5² - 3/5 5'log 5⁻³ + 7/10 5'log 5⁻²
    = 2/5 + 9/5 - 14/10
    = 11/5 - 14/10
    = 4/5
  • 5log5 = 1
    maka
    1/5  5log 25 - 3/5  5log (1/125) + 7/10  5log (1/25)
    = 1/5  5log5^2  -  3/5  5log 5^(-3) + 7/10  5log 5^-2
    = 2/5 5log 5 - (-3)x3/5 5log 5 + 7/10 x(-2) 5log5
    = 2/5 + 9/5 - 14/10
    = 11/5 - 14/10
    = 22/10 - 14/10
    = 8/10
    = 4/5