1/5 5log25 - 3/5 5log1/125+7/10 5log1/25=
Matematika
aldhava
Pertanyaan
1/5 5log25 - 3/5 5log1/125+7/10 5log1/25=
2 Jawaban
-
1. Jawaban MathSolver74
1/5 5'log 5² - 3/5 5'log 5⁻³ + 7/10 5'log 5⁻²
= 2/5 + 9/5 - 14/10
= 11/5 - 14/10
= 4/5 -
2. Jawaban subebe
5log5 = 1
maka
1/5 5log 25 - 3/5 5log (1/125) + 7/10 5log (1/25)
= 1/5 5log5^2 - 3/5 5log 5^(-3) + 7/10 5log 5^-2
= 2/5 5log 5 - (-3)x3/5 5log 5 + 7/10 x(-2) 5log5
= 2/5 + 9/5 - 14/10
= 11/5 - 14/10
= 22/10 - 14/10
= 8/10
= 4/5