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Sebuah benda diletakkan 60 cm didepan cermin jika tinggi benda tersebut 3cm dan focus cermin cekung 15 cm tentukan
Letak bayangan
Perbesaran bayangan
Tinggi

1 Jawaban

  • pemantulan cahaya

    cermin cekung
    f = 15 cm
    s = 60 cm ... ruang 3
    h = 3 cm

    a][ jarak bayangan
    1/s + 1/s' = 1/f
    1/60 + 1/s' = 1/15
    1/s' = 1/15 - 1/60
    1/s' = 4/60 - 1/60
    1/s' = 3/60
    s' = 60/3 = 20 cm ✔️
    (ruang 2)

    b][ perbesaran
    m = a' / s
    m = 20 / 60
    m = ⅓ kali ✔️

    c][ tinggi bayangan
    h' = m h
    h' = ⅓ • 3
    h' = 1 cm ✔️


    atau

    perbesaran
    m = f / (s - f)
    m = 15 / (60 - 15) = 15/45 = ⅓

    jarak bayangan
    s' = m s = ⅓ • 60 = 20 cm

    tinggi bayangan
    h' = m h = ½ • 3 = 1 cm

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