Matematika

Pertanyaan

16 ¹/² - 27 ²/³ + 25¹/5 - {1/8}¹/³ =

1 Jawaban

  • akar 16 - 3akar 27^2 + 25/5 - 3akar 1/8 = 4 - 3akar(3^3)^2 + 5 - 3akar (1/2^3) = 3akar3^6 + 5 - 1/2^3/3 = 3^6/3 + 5 - 1/2 = 3^2 + 5 - 1/2 = 9 + 5 - 0,5 = 14 - 0,5 = 13,5
    jika kurang dimengerti tolong ditanyakan

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