f(x) = 2x² - 3 f(a) = 47 tentukan nilai a ! tolong pake cara... mksssshhh

Kelas 10 Matematika
Bab Persamaan Kuadrat

f(a) = 47
2a² - 3 = 47
2a² - 3 - 47 = 0
2a² - 50 = 0
2 (a² - 25) = 0
a² - 25 = 0
(a + 5) (a - 5) = 0
a + 5 = 0
a = -5

a - 5 = 0
a = 5

Jadi, a = -5 atau a = 5