log (x-2) + log (x+1) = log (7-x) tolong dong, pake caranya

[tex] log(x-2)(x+1)=log(7-x) (x-2)(x+1)= 7-x x^{2} -x-2=7-x x^{2} -x+x-2-7=0 x^{2} -7=0 (x+ \sqrt{7})(x- \sqrt{7}) x= -\sqrt{7} x=+ \sqrt{7} [/tex]