Matematika

Pertanyaan

tolong di jawabnya kak
tolong di jawabnya kak

1 Jawaban

  • [1] 6p - q = 1 >> p = 1 + q/ 6 (1)
    4p - 3q + 4 = 0 (2)

    substitusikan (1) ke (2)
    4(1 + q / 6) - 3q + 4 = 0
    2(1 + q / 3) - 3q + 4 = 0
    2 + 2q - 9q + 12 = 0
    2q - 9q = -2 - 12
    -7q = -14
    q = -14/-7
    q = 2

    •6p - q = 1
    6p - 2 = 1
    6p = 1 + 2
    p = 3/6
    p = 1/2

    [2] a - 2b = 4
    3b - 5a = 6

    a = 4 + 2b

    3b - 5a = 6
    3b - 5 (4 + 2b) = 6
    3b - 20 - 10b = 6
    3b - 10b = 6 + 20
    -7b = 26
    b = - 26/7

    3b - 5a = 6
    3 ( -26 / 7 ) - 5a = 6
    - 78 / 7 - 5a = 6
    -5a = 6 + 78/7
    -5a = 120/7
    a = - 24/7