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Matematika
sulthan80
Pertanyaan
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1 Jawaban
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1. Jawaban raisawiratmanap0cy4q
[1] 6p - q = 1 >> p = 1 + q/ 6 (1)
4p - 3q + 4 = 0 (2)
substitusikan (1) ke (2)
4(1 + q / 6) - 3q + 4 = 0
2(1 + q / 3) - 3q + 4 = 0
2 + 2q - 9q + 12 = 0
2q - 9q = -2 - 12
-7q = -14
q = -14/-7
q = 2
•6p - q = 1
6p - 2 = 1
6p = 1 + 2
p = 3/6
p = 1/2
[2] a - 2b = 4
3b - 5a = 6
a = 4 + 2b
3b - 5a = 6
3b - 5 (4 + 2b) = 6
3b - 20 - 10b = 6
3b - 10b = 6 + 20
-7b = 26
b = - 26/7
3b - 5a = 6
3 ( -26 / 7 ) - 5a = 6
- 78 / 7 - 5a = 6
-5a = 6 + 78/7
-5a = 120/7
a = - 24/7